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Count the occurance and position of 1 in a binary number.

 Write a program to count the occurrence of 1 and print it's position of a number which is converted to binary number.


import java.util.*;


public class DigitCount {

public static void toBinary(int decimal){    

     int binary[] = new int[100];    

     int index = 0;    

     while(decimal > 0){    

       binary[index++] = decimal%2;    

       decimal = decimal/2;    

     }    

     int count = 0, lo=0;

     int loc[] = new int[100];

     

     for(int i = index-1;i >= 0;i--){    

          if(binary[i] == 1) {

          count += 1;

          loc[lo++]=i;

          }

     }

     

     System.out.print(count);

     

     for(int i = lo-1;i >= 0;i--) {

    System.out.print("#"+loc[i]);

     }

}    

public static void main(String args[]) {

Scanner sc = new Scanner(System.in);

int n= sc.nextInt();

toBinary(n);

}

}







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